![]() Next place two pins on the other side of the normal in such a way that these two pins are in a straight line with the reflection of the two pins on the other side of the normal. Now remove the mirror and the pins and join the pin marks to the normal. It will be seen that the angles which the lines make on both sides of the normal will be equal (refer to the attached image). So, if one line represents the incident ray - the ray which is travelling from the source of light - and the other line represents the reflected ray - the ray of light which has been reflected - it is proved that the angle which the incident ray makes to the normal is always equal to the angle which the reflected ray makes to the normal i. Since the lines representing the normal and the incident and reflected rays are all represented on the sheet of plain paper, the incident ray, the reflected ray and the normal are coplanar.A light ray reflects from a mirror, as shown in the diagram. The length ? equals four centimeters, the length ? equals four centimeters, and the length ? equals five centimeters. So, this question is about a light ray reflecting from a mirror. Looking at the diagram, this right here is the incident light ray and this here is the reflected ray. Finally, this gray rectangle here is the mirror that the light ray reflects from. We can recall that when light reflects from a surface, it does so according to a particular law. This law is known as the law of reflection, and it works as follows. At the point where the incident ray meets the reflecting surface, we can draw something called the normal to the surface. In the diagram from the question, the normal to the surface is this dashed line. The normal is a line that is perpendicular to the surface. That is, it meets the surface at an angle of 90 degrees. The angle between the incident light ray and the normal to the surface is known as the angle of incidence and is commonly labeled as ?.
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